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tankabanditka [31]
4 years ago
13

Which quadratic equation is equivalent to (x + 2)2 + 5(x + 2) – 6 = 0

Mathematics
1 answer:
satela [25.4K]4 years ago
3 0
If we expand that binomial and at the same time distribute the 5 into the set of parenthesis, what we have is this: x^2+4x+4+5x+10-6=0.  Combining like terms we have x^2+9x+8=0.  As far as I can tell, that is the answer you are looking for, although there are no choices.
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Read the following lines from the poem “At the Tourist Centre in Boston.”
iren2701 [21]
"Irate" is the word among the choices given in the question that <span>best describes the speaker’s tone. The correct option among all the options that are given in the question is the third option or the penultimate option or option "C". I hope that this is the answer that has come to your desired help.</span>
7 0
3 years ago
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Y=2x/a+2b solve for a
mina [271]
Solve for a.

y=2x/a+2b

Multiply both sides by a.

ay=2ab+2x

Add -2ab to both sides.

ay+−2ab=2ab+2x+−2ab

−2ab+ay=2x

Factor out variable a.

a(−2b+y)=2x

Divide both sides by -2b+y.

a(−2b+y) / −2b+y = 2x / −2b+y

a = 2x / −2b+y

6 0
3 years ago
Pls explain how to do this
8090 [49]

Answer:

3 1/12 miles

Step-by-step explanation:

6\frac{3}{4} -3\frac{2}{3} \\\\=\frac{27}{4} -\frac{11}{3}\\\\ =\frac{81}{12} -\frac{44}{12} \\\\=\frac{37}{12}\\\\=3\frac{1}{12}

Make them into mixed fractions and then find the least common denominator (12). solve.

5 0
3 years ago
I need to rewrite d and h without the use of fractional or negative exponents by using radicals, how I do that???
jolli1 [7]

Answer:

The pencil marks on your page show you exactly how to do that.

Step-by-step explanation:

Take advantage of two rules of exponents:

\sqrt[n]{x}=x^{\frac{1}{n}}\\\\x^{-n}=\dfrac{1}{x^{n}}

(d)\quad x^{\frac{-1}{5}}=\dfrac{1}{x^{\frac{1}{5}}}=\dfrac{1}{\sqrt[5]{x}}\\\\(h)\quad x^{\frac{-2}{11}}=\dfrac{1}{x^{\frac{2}{11}}}=\dfrac{1}{\sqrt[11]{x^{2}}}

3 0
3 years ago
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PLEASE PLEASE HELP, I'll give brainliest<br> easy
Oxana [17]
C, this class is really hard, if u need tutoring contact me
5 0
3 years ago
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