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BartSMP [9]
3 years ago
9

Which inequality is the solution to 2(6−4x)>18−2x?x -1x > -3

Mathematics
2 answers:
givi [52]3 years ago
7 0

Answer:

What the other dude said

Step-by-step explanation:

bruh

vekshin13 years ago
6 0

Answer:

<h2>x < - 1 </h2>

Step-by-step explanation:

2(6−4x)>18−2x

Multiply the terms in the bracket

12 - 8x > 18 - 2x

Move 12 to the other side of the inequality

- 8x > 18 - 12 - 2x \\  - 8x > 6 - 2x

Move - 2x to the other side of the inequality

- 8x + 2x > 6 \\  - 6x > 6

Divide both sides by - 6

\frac{ - 6x}{ - 6}  >  -  \frac{6}{6}  \\ x >  - 1

Reverse the sign

We have the final answer as

<h3>x < - 1</h3>

Hope this helps you

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Anna35 [415]

Answer:

\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

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Step-by-step explanation:

Given

\frac{b}{7a^2c}

Express the denominator as 35a^3c^3

To do this, we divide35a^3c^3 by the denominator

\frac{35a^3c^3}{7a^2c} = 5ac^2

So, the required fraction is:

\frac{b}{7a^2c} * \frac{5ac^2}{5ac^2}

\frac{5abc^2}{35a^3c^3}

Hence:

\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

Given

\frac{a}{a - 4}

Express the denominator as 16 - a^2

Multiply the fraction a+4/a+4

So, we have:

\frac{a}{a - 4} * \frac{(a + 4)}{(a + 4)}

Apply difference of two squares to the denominator

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Take the additive inverse of the numerator and denominator

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88 Ounces

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