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3 years ago

Harvey is 3 times as old as Jane. The sum of their ages is 48 years. Find the age of each.

2 answers:

6 0

Alright, let's answer this -

Half of 48 is 24...

Half of 24 is 12...

12 three times is 36...

36 + 12 is equal to 48. =)

adoni [48]3 years ago

3 0

H = Harvey
j = Jane

Harvey is 3 times as old as Jane = 3 times j

The sum of their ages is 48 years.

sum = addition

The keyword is means use a equal sign so..

h + j = 48

h = 3 times j

3j + j = 48
4j = 48
4j / 4 = 48 /4
j = 12

j = 12

Now lets find for Harvey. Harvey = 3 times j

Harvey = 3j = 3 times 12 = 36

Jane = 12
Harvey = 36

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Step-by-step explanation:

Given

See attachment for graph

Solving (a): Explain how the standard deviation is calculated.

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To do this, we divide the sum of the products of grade and number of students by the total number of students;

i.e.

$\bar x = \frac{\sum fx}{\sum f}$

So, we have:

$\bar x = \frac{50 * 1 + 57 * 2 + 60 * 4 + 65 * 3 +72 *3 + 75 * 12 + 77 * 10 + 81 * 6 + 83 * 6 + 88 * 9 + 90 * 12 + 92 * 12 +95 * 2 + 99 * 4 + 100 * 5}{1 + 2 + 4 + 3 +3 + 12 + 10 + 6 + 6 + 9 + 12 + 12 +2 + 4 + 5}$

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Next, calculate the variance using the following formula:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f}$

i.e subtract the mean from each dataset; take the squares; add up the squares; then divide the sum by the number of dataset

So, we have:

$\sigma^2 = \frac{1 * (50 - 82.76)^2 +...................+ 5 * (100 - 82.76)^2}{91}$

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2 years ago

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Height = 4 in

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