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erastova [34]
3 years ago
8

I think I got this wrong I need help

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

I think 3/4 will be the answer if you let

(-5 2) =(x1 y1)

(3 8) =( x2 y2)

y1-y2/x2-x2

8-2/3+5

6/8

3/4

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A man mixed 2 teaspoons of sugar into his large coffee but then added one more teaspoon of sugar because it was now sweet enough
german
The answer is 3:1, 3 to 1, or 3/1
4 0
3 years ago
There are 14 rows of seats in a cinema.
xeze [42]

Answer:

24 tickets were not sold

Step-by-step explanation:

Here, we want to get the number of unsold tickets

In each row, there are 15 seats

In the Cinema, there are 14 rows

The total number of seats is thus;

15 * 14 = 220 seats

If all the 220 seats were booked, the total amount of ticket sales would have been;

220 * 6.5 = £1430

But in this case, the amount generated is £1,274

Hence, the difference in these amounts will be;

1430 - 1274 = £156

To get the number of tickets unsold, we have to divide the amount here by the price per unit ticket

Mathematically, we have this as;

£156/£6.5 = 24

3 0
3 years ago
I need 18 please <br><br> ???
dolphi86 [110]

Omg at school recently we learned the exact same thing.

(x-8)+4x=7x-16

5x-8=7x-16

-5x    -5x

-----------------

-8=2x-16

+16    +16

-----------------

8=2x

4=x

7(4)-16

The answer is 12*

4 0
3 years ago
Write the terms a 1a1​, a 2a2​, a 3a3​, and a 4a4 of the following sequence. If the sequence appears to​ converge, make a conjec
Arturiano [62]

Answer:

Step-by-step explanation:

WE are given that a_n = \frac{(-1)^{n+1}}{5n-4}. Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then

a_1 = \frac{(-1)^2}{5(1)-4} = \frac{1}{1}= 1

a_2 = \frac{(-1)^3}{5(2)-4} = \frac{-1}{6}

a_3 = \frac{(-1)^4}{5(3)-4} = \frac{1}{11}= 1

a_4 = \frac{(-1)^5}{5(4)-4} = \frac{-1}{16}= 1

Note that as n increase, a_n gets closer to 0. So, the limit of this sequence is 0.

6 0
3 years ago
11) f(x) = -x + 4x3 – 2x + 2
daser333 [38]

Answer:

Step-by-step explanation:

3 0
3 years ago
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