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Darya [45]
3 years ago
6

Determine the amplitude or period as requested. Period of a y = - 1/3 * sin x - 1/3 pi/3 1/3 d 2pi

Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

Period = 2\pi

Step-by-step explanation:

Given

y = -\frac{1}{3} * \sin(x - \frac{1}{3})

Required

Determine the period

A sine function is represented as:

y =A \sin(Bx + C) + D

Where

Period = \frac{2\pi}{B}

By comparing:

y =A \sin(Bx + C) + D and y = -\frac{1}{3} * \sin(x - \frac{1}{3})

Bx = x

So:

B = 1

So, we have:

Period = \frac{2\pi}{B}

Period = \frac{2\pi}{1}

Period = 2\pi

Hence, the period of the function is 2\pi

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Answer:

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In this question, we want to compare several numbers with different denominators and find out which number is the least. To compare this number, we have to change the denominator into the same number by finding the least common multiple (LCM) of the 4 numbers. The factor of each number will be:

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We can find the LCM by multiplying a higher exponent of each prime number. The LCM will be:3^1 * 5^1 * 2^3 = 120

Each number will be:

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As you can see, the team with the lowest chance to play is Bulldogs = 45/120

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