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Zinaida [17]
3 years ago
13

4 1/2 divided by 2 3/4 equals what and this is mixed number

Mathematics
2 answers:
iren2701 [21]3 years ago
6 0

Answer:

1 7/11

Step-by-step explanation:

NARA [144]3 years ago
3 0

Answer: 1 7/11

please mark as brainliest

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Wittaler [7]
4(3+2(5))
4(3+10)
4(13)
52

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Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
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Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
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Answer:

9-foot piece is better deal by $0.03 per foot

Step-by-step explanation:

2.80/8 = $0.35 per foot (for 8-foot piece)

2.88/9 = $0.32 per foot (for 9-foot piece)

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3 years ago
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