(1) For the parabola on the bottom row, the domain would be R and the range would be y ≥ -5
(2) For the hyperbola on the bottom row, the domain would be R\{3} (since there is an asymptote at x = 3) and the range would be R\{4} (since there is an asymptote at y = 4)
(3) For the square root function on the bottom row, the domain would be x ≥ -5 and the range would be (-∞, -2]
(4) For the function to the very right on the bottom row, the domain would be R and the range would be (-∞, -3]
Answer:
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9514 1404 393
Answer:
(f×g)(2) = 3/4
Step-by-step explanation:
For each of the functions, put 2 where x is and evaluate the expression.
f(2) = (3 -2)/(2² +4) = 1/8
g(2) = 3×2 = 6
Then the product is ...
(f×g)(2) = f(2)×g(2) = (1/8)×6 = 6/8
(f×g)(2) = 3/4
Answer:
your answer is as follows
Step-by-step explanation:
5x+20=3x+60
2x=40
x=20
(equating the slopes)
