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likoan [24]
3 years ago
9

25/22 start fraction, 22, divided by, 25, end fraction of a number is what percentage of that number?

Mathematics
1 answer:
densk [106]3 years ago
5 0

Answer:

88%

Step-by-step explanation:

The percentage of a number or fraction can be derived by multiplying the given value by 100%.

Given the fraction 22/25, the percentage of the fraction will be

gotten by multiplying the fraction by 100%

22/25 × 100%

= 22×4

= 88%

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Find n.<br> 35/49=5/n<br> n=_____
ivolga24 [154]
N = (5 * 49) / 35 = 7
3 0
3 years ago
Find dy/dx by implicit differentiation for the following equation. e^x^2=7x+5y+3
lesantik [10]

Answer:

\displaystyle \frac{dy}{dx} = \frac{2e^{2x} - 7}{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Implicit Differentiation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

eˣ Derivative: \displaystyle \frac{d}{dx}[e^u] = u'e^u

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle (e^x)^2 = 7x + 5y + 3

<u>Step 2: Differentiate</u>

  1. Rewrite [Exponential Rule - Powering]:                                                          \displaystyle e^{2x} = 7x + 5y + 3
  2. Implicit Differentiation:                                                                                   \displaystyle \frac{d}{dx}[e^{2x}] = \frac{d}{dx}[7x + 5y + 3]
  3. [Derivative] eˣ derivative:                                                                                \displaystyle 2e^{2x} = \frac{d}{dx}[7x + 5y + 3]
  4. [Derivative] Basic Power Rule:                                                                       \displaystyle 2e^{2x} = 1 \cdot 7x^{1 - 1} + 1 \cdot 5y^{1 - 1}\frac{dy}{dx}
  5. [Derivative] Simplify:                                                                                       \displaystyle 2e^{2x} = 7 + 5\frac{dy}{dx}
  6. [Derivative] [Subtraction Property of Equality] Subtract 7 on both sides:  \displaystyle 2e^{2x} - 7 = 5\frac{dy}{dx}
  7. [Derivative] [Division Property of Equality] Divide 5 on both sides:            \displaystyle \frac{2e^{2x} - 7}{5} = \frac{dy}{dx}
  8. [Derivative] Rewrite:                                                                                       \displaystyle \frac{dy}{dx} = \frac{2e^{2x} - 7}{5}

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives - Implicit Differentiation

Book: College Calculus 10e

5 0
3 years ago
Does the graph represent a function? yea or no
xenn [34]

Answer:

No

Step-by-step explanation:

7 0
2 years ago
Which ordered pair is the vertex of y= |x+5|?
ddd [48]
The vertex for an absolute value equation is the when the expression inside the absolute symbol equals zero.
when x+5=0, x=-5
so the vertex is at (-5,0)
5 0
3 years ago
Solve for x. <br> X^ 3 =−216
bagirrra123 [75]
This isn't really a question of math, but rather memorization. I know from memory that this is -6, and -6 * -6 * -6 = -216. 
4 0
3 years ago
Read 2 more answers
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