Answer: the integers are 6 and 23
Step-by-step explanation:
Let x represent one of the integers.
Let y represent the other integer.
The product of the integers is 138. This means that
xy = 138 - - - - - - - - - -1
One of the integers is seven less than five times the other integer. This means that
x = 5y - 7
Substituting x = 5y - 7 into equation 1, it becomes
y(5y - 7) = 138
5y² - 7y = 138
5y² - 7y - 138 = 0
5y² + 23y - 30y - 138 = 0
y(5y + 23) - 6(5y + 23)
y - 6 = 0 or 5y + 23 = 0
y = 6 or y = - 23/5
The only possible value of y is 6
x = 138/y = 138/6
x = 23
Answer:
18
Step-by-step explanation:
You have to divide both sides by 12 inorder to remain with the f on the other side since you want to find the value of f.
12f/12=216/12
F=18
I hope this helps
It's 6!
When you multiply both the numerator and denominator by the same number, you will have an equivalent to the fraction you started with because the new fraction can be reduced to the original fraction.
2/3 = 4/6 = 6/9 = 8/12 = 10/15 = 12/15 etc.
