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zysi [14]
3 years ago
11

Find the amount on rupees 5000 for 2 years at 8% per annum compounded annually​

Mathematics
1 answer:
DENIUS [597]3 years ago
6 0

Answer:

27/25 * 5000 =5400

27/25 * 5400 = 5832 rupee

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Find the highest common factor of 32 and 80
valina [46]
32=2*2*2*2*2=2^5
80=2*2*2*2*5

hcf = 2*2*2*2=2⁴=16
3 0
2 years ago
Read 2 more answers
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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3 years ago
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Masja [62]

Answer:

if the "x" is a multiplication symbol, the answer is 2.

Step-by-step explanation:

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2 years ago
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Fittoniya [83]

Answer:

The highest would be the letter B and the lowest would be letter C if the pat is what you need to know.

Hope it helps :)

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2 years ago
Which statement is always true?
Goshia [24]
I’m pretty sure A is true <3
6 0
2 years ago
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