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MAVERICK [17]
3 years ago
14

Find the 12th term of the sequence which has a first term of 14 and has a common ratio of 1.03

Mathematics
2 answers:
nirvana33 [79]3 years ago
4 0
A(n)=a × r^n-1
A(12)= 14 x 1.03^11
A(12)=19.379
gavmur [86]3 years ago
4 0

Answer:

S_{12} = 19.376.

Step-by-step explanation:

Given  : sequence which has a first term of 14 and has a common ratio of 1.03.

To find :Find the 12th term of the sequence .

Solution : We have given first term of 14 and has a common ratio of 1.03.

Sum of n terms ( S_{n} = a r^{n-1}.

Where, a = first term , r = common ratio and n = number of terms .

Then, Plug the values a = 14 , r = 1.03 , n = 12.

S_{12} = 14 (1.03)^{12-1}.

S_{12} = 14 (1.03)^{11}.

S_{12} = 14 ( 1.384).

S_{12} =19.376.

Therefore, S_{12} = 19.376.

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