Question

Find the 12th term of the sequence which has a first term of 14 and has a common ratio of 1.03

Answer 1

A(n)=a × r^n-1
A(12)= 14 x 1.03^11
A(12)=19.379

Answer 2

Answer:

$S_{12} = 19.376$.

Step-by-step explanation:

Given  : sequence which has a first term of 14 and has a common ratio of 1.03.

To find :Find the 12th term of the sequence .

Solution : We have given first term of 14 and has a common ratio of 1.03.

Sum of n terms ( $S_{n} = a r^{n-1}$.

Where, a = first term , r = common ratio and n = number of terms .

Then, Plug the values a = 14 , r = 1.03 , n = 12.

$S_{12} = 14 (1.03)^{12-1}$.

$S_{12} = 14 (1.03)^{11}$.

$S_{12} = 14 ( 1.384)$.

$S_{12} =19.376$.

Therefore, $S_{12} = 19.376$.