PLS HELP: How do you solve x^2-ax-6a^2=0 by completing the square?
2 answers:
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The Fundamental Theorem of Calculus regarding geometry states that
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
and 
into 
![[2 (b)^{2}]-[2 (1)^{2}] = 240](https://tex.z-dn.net/?f=%5B2%20%28b%29%5E%7B2%7D%5D-%5B2%20%281%29%5E%7B2%7D%5D%20%3D%20240%20)
Hence the limit of the area under is between and
Where F is the indefinite integral of
The first step is to integrate
Then substitute the value of
Hence the limit of the area under