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3 years ago

11

Express 0.55% a precent

1 answer:

cupoosta [38]3 years ago

4 0

0.55%*100 = 55% is the answer

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The ribbon was 3 1/4 inches wide and had an area of 19 1/2 square inches. What is the length of the ribbon? Please Help Will Giv

miv72 [106K]

Hello!

The formula for finding area is l × w

If the area is 19 ½ inches and it was 3 ¼ inches wide, then the length will be 19 ½ ÷ 3 ¼ (Area ÷ Width)

$19 \frac{1}{2} \div 3 \frac{1}{4}$

Change both to improper fraction

$19 \frac{1}{2} = \frac{39}{2}$

$3 \frac{1}{4} = \frac{13}{4}$

$\frac{39}{2} \div \frac{13}{4}$

Keep 39/2
Change ÷ to ×
Flip 13/4 = 4/13

$\frac{39}{2} \times \frac{4}{13} = \frac{156}{26} = 6$

$\framebox {The length of the ribbon is 6 inches}$

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3 years ago

Read 2 more answers

Find the value of the next term in the sequence.<br><br> 28, 25, 22, 19,

Katena32 [7]

Answer:

The answer would be 16

Step-by-step explanation:

The answer would be 16 because after each number your subtracting 3.

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3 years ago

70 POINTS PLEASE HELP!! Use the two equations: f (x) =x^2 and g (x) =4x+1 to determine the solutions to the following function o

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3 years ago

The shown bellow question answer

Serhud [2]

Answer:

The area of the shape can be divided into the area of the rectangle, and the area of the semi-circle.

The area of the rectangle can be found by $11*4=44$

The area of a semi-circle can be found with the formula $\frac{1}{2} \pi r^2$ where r is the radius.

Since we know the diameter of the semi-circle is 4,

the radius will be 4 ÷ 2 = 2.

Therefore, the area of the semi-circle is $\frac{1}{2}\pi 2^2=\frac{1}{2}\pi*4=2\pi$

Therefore, the area of the shape is $44+2\pi$ or $50.283cm^2$ (3 decimal places)

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2 years ago

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I have eight coupons that are all worth -.25

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3 years ago