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A customer wants rhombus-shaped tiles for his countertops. The height is 3 inches and the area of each tile is 21.6 in.2. What i

julsineya [31]

The length of each side of the tiles is 7.2 in

<u>Explanation:</u>

Given:

Height of the tile, h = 3 in

Area of each tile, A = 21.6 in²

Length of each side, a = ?

We know:

A rhombus is a type of quadrilateral whose opposite sides are parallel and equal.Also, the opposite angles of a rhombus are equal and the diagonal intersect each other perpendicularly.

To find the area of a rhombus when the measures of its height and side length are given, use the formula

A = Base X height

21.6 in² = a X 3 in

a = 7.2 in

Therefore, the length of each side of the tiles is 7.2 in

3 0

3 years ago

A restaurant has 26 tables in its dining room. It takes the waitstaff 10 minutes to clear and set 4 tables. At this rate, how lo

lutik1710 [3]

Well, its 10 for 4. so 8 is 20, 12 is 30, 16 is 40 20 is 50, and 24 is 1 hour, 2 tabels is half the time so 5 min... so it would take -1 hour and 5 min

5 0

3 years ago

Read 2 more answers

The quotient of 2 times a number and 19

Reptile [31]

This one is worded oddly, but I think it's going to be:
(2x)/19

3 0

3 years ago

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Question 45 A length of pipe that weighs 45 pounds is cut into two pieces. One of the pieces is 3 feet long and weighs 18 pounds

dmitriy555 [2]

Answer: 4.5 pounds.

Step-by-step explanation:

Given : Weight of original pipe =45 pounds

Weight of first piece = 18 pounds

Then, Weight of other piece = 45- 18 = 27 pounds

Length of first piece = 3 feet

Let x be the length of other piece.

As length is directly proportional to weight.

Then, $\dfrac{x}{27}=\dfrac{3}{18}$

$\Rightarrow\ \dfrac{x}{27}=\dfrac{1}{6}\\\\\Rightarrow\ x=\dfrac{1}{6}\times27 =4.5$

Hence, the he length of the other piece = 4.5 pounds.

7 0

3 years ago

Solution A is an $80\%$ acid solution. Solution B is a $30\%$ acid solution. (a) Find the amount of Solution A (in mL) that must

Irina-Kira [14]

Answer:

(a) $2000\text{ ml}$ (b) $40\text{ ml and }60\text{ ml}$ (c)NO

Step-by-step explanation:

GIVEN: Solution A is an $\$80\%$ acid solution. Solution B is a $\$30\%$ acid solution.

TO FIND: (a) Find the amount of Solution A (in mL) that must be added to $500 \text{ml}$ of Solution B in order to produce a $70\%$ acid solution. (b) Find the amount of Solution A and Solution B (in mL) that can be combined in order to form a $100 \text{ml}$ solution that is $50\%$ acid. (c) Does there exist a combination of Solution A and Solution B that is $90\%$ acid.