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3 years ago

9sin(Θ)-7=0. Solve the trigonometric equation

Mathematics

1 answer:

djverab [1.8K]3 years ago

6 0

Step-by-step explanation:

here's the answer to your question

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What is the length of Line segment B C? 9 units 11 units 15 units 16 units

denpristay [2]

Answer:

15 units

Step-by-step explanation:

The picture of the question in the attached figure

we know that

In the right triangle ABC

Applying the Pythagorean Theorem

$AB^2=AC^2+BC^2$

we have

$AB=17\ units\\AC=8\ units$

substitute the given values

$17^2=8^2+BC^2$

solve for BC

$289=64+BC^2\\BC^2=289-64\\BC^2=225\\BC=15\ units$

3 0

3 years ago

Read 2 more answers

0.50x-6=4 this is algebra 1 can you please help me

horsena [70]

0.50x-6=4

move -6 to the other side

sign changes from -6 to 6

0.50x-6+6= 4+6

0.50x= 10

divide by 0.50 for both sides

0.50/0.50x= 10/0.50

x= 20

Answer: x= 20

5 0

3 years ago

Read 2 more answers

Multiply using FOIL or Table method (x + 4) (x + 5)

mylen [45]

Answer:

${x}^{2} + 9x + 20$

Step-by-step explanation:

1) Use FOIL method: (a + b) (c + d) = ac + ad + bc + bd.

${x}^{2} + 5x + 4x + 20$

2) Collect like terms.

${x}^{2} + (5x + 4x) + 20$

3) Simplify.

${x}^{2} + 9x + 20$

Therefor, the answer is x² + 9x + 20.

5 0

3 years ago

Find the length of a leg of a right triangle (in inches) if the other leg measures 9 in. and the hypotenuse measures 19 in. Roun

kipiarov [429]

Answer:

a = 16.733

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2

a^2 + 9^2 = 19^2

a^2 = 19^2 - 9^2

a^2 = 361-81

a^2 =280

Taking the square root of each side

sqrt(a^2) = sqrt(280)

a = 16.73320053

Rounding to the nearest thousandth

a = 16.733

5 0

3 years ago

The product of (3 − 4i) and____is 25.

LiRa [457]

$(3-4i)(a+bi)=25\qquad\text{use FOIL method}\\\\(3)(a)+(3bi)+(-4i)(a)+(-4i)(bi)=25+0i\\\\3a+3bi-4ai-4bi^2=25+0i\\\\3a+3bi-4ai-4b(-1)=25+0i\\\\3a+3bi-4ai+4b=25+0i\\\\(3a+4b)+(3b-4a)i=25+0i\\.\qquad\qquad\qquad\qquad\Downarrow\\\\3a+4b=25\ and\ 3b-4a=0\\\\3b-4a=0\qquad\text{add 4a to both sides}\\\\3b=4a\qquad\text{divide both sides by 3}\\\\b=\dfrac{4}{3}a\qquad\text{substitute it to the first equation}\\\\3a+4\left(\dfrac{4}{3}a\right)=25\\\\3a+\dfrac{16}{3}a=25\qquad\text{multiply both sides by 3}$

$9a+16a=75\\\\25a=75\qquad\text{divide both sides by 25}\\\\\boxed{a=3}\qquad\text{put the value of a to}\ b=\dfrac{4}{3}a:\\\\b=\dfrac{4}{3}(3)\\\\\boxed{b=4}\\\\Answer:\ \boxed{(3-4i)\underline{(3+4i)}=25}$

6 0

3 years ago