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Nikitich [7]
3 years ago
13

A new graph is formed from y = 5x by changing the slope to 9 and y-intercept to 8. Which statement about the new relationship is

true?
The new graph has a steeper slope and a y-intercept of 13.

The new graph has a steeper slope and y-intercept of 8.

The new graph has a less steep slope and a y-intercept of 13

The new graph has a less steep slope and a y-intercept of 8
Mathematics
1 answer:
shusha [124]3 years ago
8 0

Answer:

The new graph has a steeper slope and a y-intercept of 8.

Step-by-step explanation:

From Analytical Geometry, we define a straight line by following first order polynomial (linear function):

y = m\cdot x + b (1)

Where:

x - Independent variable.

y - Dependent variable.

b - y-Intercept.

m - Slope.

And the slope represents the change in dependent variable (\Delta y) divided by the change in independent variable (\Delta x). That is:

m = \frac{\Delta y}{\Delta x}

If m_{1} > 0 and m_{2} > m_{1}, then the new line is steeper with respect to the original line.

Let y = 5\cdot x, its slope and y-intercept are 5 and 0, respectively. If slope is changed into 9 and y-intercept becomes 8, then the new graph has a steeper slope and a y-intercept of 8.

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Answer:

Example Problem

Solve 2x+3=15.

Example Answer

x=6

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Step-by-step explanation:

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Prove the divisibility:<br><br>45^45·15^15 by 75^30
garri49 [273]

Answer:

3^{75}.

Step-by-step explanation:

We have been an division problem: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(9*5)^{45}=9^{45}*5^{45}

15^{15}=(3*5)^{15}=3^{15}*5^{15}

75^{30}=(15*5)^{30}=15^{30}*5^{30}

Substituting these values in our division problem we will get,

\frac{9^{45}*5^{45}*3^{15}*5^{15}}{15^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{9^{45}*5^{(45+15)}*3^{15}}{15^{30}*5^{30}}

\frac{9^{45}*5^{60}*3^{15}}{15^{30}*5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{(3*3)^{45}*5^{60}*3^{15}}{(3*5)^{30}*5^{30}}

\frac{3^{45}*3^{45}*5^{60}*3^{15}}{3^{30}*5^{30}*5^{30}}

Using power rule of exponents a^n*a^m=a^{n+m} we will get,

\frac{3^{(45+45+15)}*5^{60}}{3^{30}*5^{(30+30)}}

\frac{3^{105}*5^{60}}{3^{30}*5^{60}}

\frac{3^{105}}{3^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{105}}{3^{30}}=3^{105-30}

3^{105-30}=3^{75}

Therefore, our resulting quotient will be 3^{75}.

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3 years ago
In the figure, c || d. what are the measures of angle 1 and angle 2?
dusya [7]

Answer:

Angle 1 = 105

Angle 2 = 75

Step-by-step explanation:

Angle 2 and angle 75 are corresponding angles.

Corresponding angles are equal.

So,

Angle 2 = 75

Angle 1 and angle 2 are linear pair angles.

Angle 1 + Angle 2 = 180

Angle 1 + 75 = 180

Angle 1 = 180 - 75

Angle 1 = 105

8 0
3 years ago
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