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Dmitry_Shevchenko [17]
3 years ago
14

PLEASE HELP I NEED THIS FAST!!!!

Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer: B


Step-by-step explanation:

Ya see here, since jason sells 15 per hour it's 15j, and since Victoria sells 22 more than him, its 15j+22

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What are prime factors of 1000?
Ede4ka [16]

Answer:

1,2,4,5,8,10,20,25,40,50,10,125,200,250,500,1000

Step-by-step explanation:

prime factorization is

1000=2*2*2*5*5*5

4 0
2 years ago
Choose all the number sentences that have a sum less than 345,195: A) 189,753 + 155,655 B) 324,675 + 19,285 C) 185,476 + 155,923
fgiga [73]

Answer:

C, D

Step-by-step explanation:

Calculate the sum of all.

C and D have less then 345,195.

That is the answer.

5 0
3 years ago
Read 2 more answers
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in theratio is 10, what is the Second numb
Zanzabum

Answer:

10:40

Step-by-step explanation:

As the left number increases by 1, the right number increases by 4. So as you can see, the left numbers go 3-4-5 while the right numbers go 12-16-20. So the answer is 10:40 because 10x4=40.

6 0
3 years ago
Read 2 more answers
HELPPPPPP !!! I seriously don't know what to write.
tresset_1 [31]

Answer:

<em>This question was previously answered on Brainly...</em>

<em>Be sure to put this into your own words.</em>

<em>Answer: check explanation for the solution </em>

<em> </em>

Step-by-step explanation:

<em> </em>

A business that offers services to people by providing many amusement and fun with gate fees

The algebraic equations to be used is the general linear equation

Y = MX + C

Where

Y = total income or money realised

M = rate or price rate

X = number of goods or services

C = flat rate or gate fees

The business can also operate differently by using exponential equation

A = P(1 + R%)^t

Where

A = profit

P = capital

R = rate

t = time

3 0
3 years ago
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