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3 years ago

8

If QR= 3x-2, RS= 2x+1, QS=6x-3, and R is between Q and S, then RS=

1 answer:

rewona [7]3 years ago

4 0

Answer:

RS = 5

Step-by-step explanation:

Since R is between Q and S , then

QS = QR + RS , that is

6x - 3 = 3x - 2 + 2x + 1

6x - 3 = 5x - 1 ( subtract 5x from both sides )

x - 3 = - 1 ( add 3 to both sides )

x = 2

Then

RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5

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