All categories

3 years ago

A 133.5 kg crate, sliding on the floor, is brought to a stop by a 54.5 N force. What is the deceleration of the crate?

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

Answer:

0.40m/s^2

Step-by-step explanation:

Given data

Mass= 133.5kg

Force F= 54.5N

The expression for the force acting is

F=ma

substitute

54.5=133.5*a

]Divide both sides by 133.5

a= 54.5/133.5

a= 0.40 m/s^2

Hence the acceleration is 0.40m/s^2

You might be interested in

Graph p>−1.6 on a number line.

Lynna [10]

You start at the number -1.6 which is on the number line, then you put the open circle on the and have the line move towards the right of the number line.

4 0

3 years ago

Braxton puts $1,275 into a savings account that earns 3% simple interest per year. How much total money will be in his account a

andrew11 [14]

Answer:

The answer would be B) 1,466.25

Step-by-step explanation:

The formula we'll use for this is the simple interest formula, or:

I= P x r x t

Where:

P is the principal amount, $1275.00.

r is the interest rate, 3% per year, or in decimal form, 3/100=0.03.

t is the time involved, 5....year(s) time periods.

So, t is 5....year time periods.

To find the simple interest, we multiply 1275 × 0.03 × 5 to get that:

The interest is: $191.25

Usually now, the interest is added onto the principal to figure some new amount after 5 year(s),

or 1275.00 + 191.25 = 1466.25.

4 0

3 years ago

Read 2 more answers

The next number in the pattern 1 5 25 125 625

chubhunter [2.5K]

5⁰ = 1
5¹ = 5
5² = 25
5³ = 125
5⁴ = 625
5⁵ = 3125

5 0

4 years ago

ASAP PLS HELP ME I NNED HELP

likoan [24]

Answer:

perimeter=40.9ft

Step-by-step explanation:

The length at the top is 10ft,the length at the bottom is 10+4ft=14ft and the other lengths are8.9ft and 8ft

perimeter=10+14+8+8.9=40.9ft

6 0

3 years ago

rt AA field party is capable of making taping observations with a standard deviation of ± 0.04 ft per 100 ft tape length. What s

beks73 [17]

Answer:

±0.0283 ft

Step-by-step explanation:

Sometimes

$E = \frac{E_{series} }{\sqrt{n} } \\E_{series} = E\sqrt{n} \\E_{series} =0.04 * \sqrt{\frac{200}{100} } \\$

E_{series} = ±0.0283 ft

3 0

3 years ago