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3 years ago

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setsuko has a rectangular piece of farbric that is 5/6 yard wide. The area of the fabric is 5/16 square yard. How long is setsuk

o's fabric

1 answer:

shepuryov [24]3 years ago

3 0

It is 3/8 in length

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What is the answer to this question ? Pls help!!

sammy [17]

The answer is B when you subtract every like term

6 0

3 years ago

Read 2 more answers

Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |

dsp73

Looks like $f(x,y)=x^2+y^2-x^2y+7$ .

$f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1$

$f_y=2y-x^2=0\implies2y=x^2$

If $x=0$ , then $y=0$ - critical point at (0, 0).
If $y=1$ , then $x=\pm\sqrt2$ - two critical points at $(-\sqrt2,1)$ and $(\sqrt2,1)$

The latter two critical points occur outside of $D$ since $|\pm\sqrt2|>1$ so we ignore those points.

The Hessian matrix for this function is

$H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}$

The value of its determinant at (0, 0) is $\det H(0,0)=4>0$ , which means a minimum occurs at the point, and we have $f(0,0)=7$ .

Now consider each boundary:

If $x=1$ , then

$f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4$

which has 3 extreme values over the interval $-1\le y\le1$ of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

If $x=-1$ , then

$f(-1,y)=8-y+y^2$

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

If $y=1$ , then

$f(x,1)=8$

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

If $y=-1$ , then

$f(x,-1)=2x^2+8$

which has 3 extreme values, but the previous cases already include them.

Hence $f(x,y)$ has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0

3 years ago

Solve the equation p/4+10=14

Gelneren [198K]

Answer:

p=16

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

15 points for someone who can answer & explain this to me thanks

iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{9}{a^2+9a+20}$ , $\frac{7a}{a^2+11a+28}$

Factor the denominators of both fractions

$\frac{9}{(a+4)(a+5)}$ , $\frac{7a}{(a+4)(a+7)}$

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

$\frac{9(a+7)}{(a+4)(a+5)(a+7)}$ , $\frac{7a(a+5)}{(a+4)(a+5)(a+7)}$ , then

$\frac{9a+63}{(a+4)(a+5)(a+7)}$ , $\frac{7a^2+35a}{(a+4)(a+5)(a+7)}$

8 0

3 years ago

Pls help. First answer marked as brainliest

Misha Larkins [42]

-2; 3-5= -2 or -5 - (-3)

-1; 4-5 or -5 - (-4) = -1

-5; -6 - (-1)= 1-6= -5

5 0

3 years ago