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3 years ago

The ratio of boys to girls in the ninth grade is 6:5. If there are 185 girls in the class, how many boys are there.

2 answers:

4 0

There are 222 boys in the class. You find this by dividing 185 by 5 which gets you 37, so you have to multiply the 6 by 37 to find the amount of boys.

anygoal [31]3 years ago

3 0

There is 222 boys and 185 girls

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Abercrombie & Fitch is having a back-to-school sale

snow_lady [41]

Answer:

that normally cost $30 each. Including 6% sales tax,

what is the total Chaz pays?

Please answer very fast!

Abercrombie & Fitch is having a back-to-school sale

with all cargo shorts 30% off. Chaz buys 3 pairs of shorts

that normally cost $30 each. Including 6% sales tax,

what is the total Chaz pays?

Please answer very fast!

Step-by-step explanation:

Abercrombie & Fitch is having a back-to-school sale

with all cargo shorts 30% off. Chaz buys 3 pairs of shorts

that normally cost $30 each. Including 6% sales tax,

what is the total Chaz pays?

Please answer very fast!

6 0

3 years ago

You are wrapping a gift box. You want to tie a ribbon around the box , so that whenever the ribbon intersects an edge of the box

Paha777 [63]

You are wrapping a gift box. The length of ribbon = length + width + height of box.

<u>Solution:</u>

Given, You are wrapping a gift box.

You want to tie a ribbon around the box, so that whenever the ribbon intersects an edge of the box, its distance to the nearest corner is 1/3 the length of the box.

We have to find how long must the ribbon be?

The figure of this problem is attached below

Now, assume we started to tie at one edge, then next we can tie at straight parallel edge, we can continue till our process ends.

Then, total length of the ribbon = length of box + width of box + height of box.

Hence, the length of ribbon = length + width + height of box.

7 0

3 years ago

A scrap metal dealer claims that the mean of his sales is "no more than $80," but an Internal Revenue Service agent believes the

Artyom0805 [142]

Answer:

There is enough not evident to support dealer's claim that his sales is no more than $80.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $80

Sample mean, $\bar{x}$ = $91

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = $21

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 80\text{ dollars}\\H_A: \mu > 80\text{ dollard}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{91 - 80}{\frac{21}{\sqrt{20}} } = 2.3425$

Now, $t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = 1.729$

Since,

The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

There is enough not evident to support dealer's claim that his sales is no more than $80.

4 0

3 years ago

Two friends have recently graduated from college and are now looking for jobs. They are debating which type of job is better: ho

Murljashka [212]

Answer:

sorry no answer for this

Step-by-step explanation:

sorry because I am in 6th

6 0

3 years ago