Answer:
0.124 mol Ag
General Formulas and Concepts:
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 7.49 × 10²² atoms Ag
[Solve] mol Ag
<u>Step 2: Identify Conversions</u>
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.124377 mol Ag ≈ 0.124 mol Ag
Topic: AP Chemistry
A simple sugars are formed
Answer:
72 g/L
Explanation:
The dissolved amount of solute is the difference between the amount you have poured and the amount that precipitated:
125 g - 35 g = 90 g
Thus, 90 grams of solute were dissolved in 1.25 liters. The saturation point is the ratio between the grams dissolved and the volume in liters:
saturation point = 90 g/1.25 L = 72 g/L
Answer:
3) Density multiplied by volume
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
So by rearranging this formula mass can be determine.
d = m/v
m = d×/v
Unit of mass when volume in mL and ddensity is g/mL
m = g/mL×mL
m = g
Example:
density = 5g/mL
volume = 3 mL
mass = ?
m = d×v
m = 5g/mL ×3 mL
m = 15 g
yes
that is truly epic if you understand