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Lemur [1.5K]
2 years ago
15

A gas in a rigid container at 25°C has a pressure of 0. 96 atm. A change in temperature causes the pressure to increase to 1. 2

5 atm. What is the new temperature of the gas? Use StartFraction P subscript 1 over T subscript 1 EndFraction equals StartFraction P subscript 2 over T subscript 2 EndFraction. â€""44. 2°C 32. 6°C 115°C 388°C.
Chemistry
1 answer:
Maksim231197 [3]2 years ago
3 0

The new temperature of the gas is 115 °C

From the question given above, the following data were obtained:

  • Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
  • Initial pressure (P₁) = 0.96 atm
  • New pressure (P₂) = 1.25 atm
  • New temperature (T₂) =?

The new temperature of gas can be obtained as follow:

\frac{P_1}{T_1}  =  \frac{P_2}{T_2} \\  \\  \frac{0.96}{298}  = \frac{1.25}{T_2}  \\  \\ cross \: multiply \\  \\ T_2 \times 0.96 = 298 \times 1.25 \\  \\ divide \: both \: side \: by \: 0.96 \\  \\T_2 =  \frac{298 \times 1.25 }{0.96}  \\  \\ T_2 = 388 \: K \\  \\ subtract \: 273 \: from \: 388 \: to \: express \: the \: answer \: im \:  \degree \: C \\  \\ T_2 = 388  - 273 \\  \\ T_2 = 115 \: \degree \: C

Therefore, the new temperature is 115 °C

Learn more about gas laws: brainly.com/question/25862018

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FYI Note => For reaction mixtures the following is a good guide to reaction response to applied system stress. Note the conclusion follows the direction the inequality symbol is pointing.  

Kc  <  Qc  => Rxn system is shifting Left

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