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kaheart [24]
3 years ago
10

The formula for the area of a

Mathematics
2 answers:
tamaranim1 [39]3 years ago
8 0

Answer:

true

Step-by-step explanation:

Sonja [21]3 years ago
7 0

Answer:

False

Step-by-step explanation:

because for area the formula is A=h b/2

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Please help me with this question. Algebra 2 is hard!!
trapecia [35]

Answer:

  • domain: {x ∈ ℝ : x ≤ 5}
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Step-by-step explanation:

<u>Domain</u>

The domain of a function is the set of x values for which the function is defined. Here, the domain is limited by the values of x that make the square root defined. That is, the expression under the radical cannot be negative:

  -3x +15 ≥ 0

  15 ≥ 3x . . . . . . add 3x

  5 ≥ x . . . . . . . . divide by 3

  x ≤ 5 . . . . . . . . put x on the left (swap sides)

The rest of the notation in the domain expression simply says x is a real number.

  domain: {x ∈ ℝ : x ≤ 5} . . . . . . matches the first choice

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<u>Range</u>

The range of a function is the set of values that f(x) can have. We know the square root can be zero or any positive number. When it is zero, f(x) = -1.

When it is a positive number, that value is multiplied by -4 and added to -1, so f(x) is a number more negative than -1. Then the range of the function is all numbers -1 and below:

  range: {y ∈ ℝ : y ≤ -1} . . . . . . matches the last choice

_____

<em>Comment on domain/range problems</em>

When working domain and range problems, it works well to have a good understanding of the domain and range limitations of the functions we usually work with: polynomials, square root, logarithm, trig functions, exponential functions. Domain and range problems generally involve combinations of these or ratios of combinations of these.

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3 years ago
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6 0
3 years ago
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Write an inequality that represents the statement "v is greater than or equal to 5"
Marizza181 [45]
Hello , 
v is greater than or equal to 5  
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jeka94

Answer:

<h2>C. -5; -135, -10,935</h2>

Step-by-step explanation:

\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{to}\ A(n)=-5\cdot3^{n-1}:\\\\A(1)=-5\cdot3^{1-1}=-5\cdot3^0=-5\cdot1=-5\\\\A(4)=-5\cdot3^{4-1}=-5\cdot3^3=-5\cdot27=-135\\\\A(8)=-5\cdot3^{8-1}=-5\cdot3^7=-5\cdot2,187=-10,935

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