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3 years ago

What is the answer to this question

Mathematics

1 answer:

posledela3 years ago

8 0

<em>The best answer from the choices provided is option </em><u>B) 56.</u>

Step-by-step explanation: Simply subtract 34 from 90.

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A projector displays an image on a wall. the area(in square feet) of the rectangular projection can be represented by

andrew-mc [135]

Answer:

The height of the projection will be (x - 5) feet.

Step-by-step explanation:

A projector displays an image on a wall. The area (in square feet) of the rectangular projection can be represented by (x² - 8x + 15).

Now to get the width and the height of the rectangular projection we have to factorize the expression (x² - 8x + 15).

Here, (x² - 8x + 15)

= x² - 3x - 5x + 15

= (x- 3)(x - 5)

Now, if the height of the projection is less than its width then, the height of the projection will be (x - 5) feet. (Answer)

3 0

3 years ago

Plz help me Jen can jump rope 80 times in 60 seconds. If she jumps at a constant ratio of seconds to jumps, how many jumps can s

uysha [10]

Answer:

The answer is 4

Step-by-step explanation:

You just divide 80 by 15.

3 0

2 years ago

Given the points (-1, 1) & (-2,-5), what is the equation of the line? *

Leni [432]

Answer:

Y=6x+7

Step-by-step explanation:

3 0

3 years ago

2 7/15÷3 2/3= anyone k ow this

avanturin [10]

U times 2 and seven and divide that by 3 and then dive 3 by 2 and that should leave u with three numbers.
514 and 1.5 times those together and there u go
105

6 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$

Coming back to x:

We have that:

$x = 3\sin{\theta}$

$\sin{\theta} = \frac{x}{3}$

Applying the arcsine(inverse sine) function to both sides, we get that:

$\theta = \arcsin{(\frac{x}{3})}$

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

8 0

3 years ago