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Mice21 [21]
3 years ago
10

I have chosen 1 playing cards .what is the probability of being red or red ace?

Mathematics
1 answer:
QveST [7]3 years ago
7 0

Answer:50% red 4/42 ace

Step-by-step explanation:

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A 12 foot ladder is placed 5 feet from the base of the building. About how high does the ladder reach?
Mariulka [41]

Answer:

7 foot

Step-by-step explanation:

8 0
3 years ago
The circumference of the base of a cylinder is 24π mm. A similar cylinder has a base with circumference of 60π mm. The lateral a
earnstyle [38]
Given that the figures are similar polygons, the ratio of their ratios should be equal to the square of the ratio of their circumference. If we let x be the lateral area of the smaller cylinder then,
                        (x/210π) = (24π/60π)²
The value of x from the equation is, 
                                     x = 33.6π
Thus, the area of the smaller cylinder is equal to 33.6π mm². 
6 0
3 years ago
Read 2 more answers
Which of the following pairs of numbers has a GCF of 1? 30 and 70 24 and 44 12 and 30 16 and 21
stiv31 [10]
Must be 16 and 21 because we can see

30 and 70 has 10 as factor
24 and 44 has 2 as factor
12 and 30 has 2 as factor and all those factors are greater than one
5 0
3 years ago
Read 2 more answers
There is a vendor at a carnival selling bags of cotton candy. Each bag of cotton candy has the same cost. She starts each day wi
umka21 [38]

Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has x dollar at the starting of each day.

Let, the cost of each cotton candy bag is y.

Now when she sells a total of 12 bags, she has $128.

x+12y=128  .....(1)

After she sells a total of 20 bags, she has $160.

x+20y=160  ....(2)

Subtract equation 1 from equation 2.

(x+20y)-(x+12y)=160-128

8y=32

y=4

Hence, the cost of each cotton candy bag is $4.

6 0
3 years ago
Sorry for the crumbled paper Can someone help me<br><br> Complete the chart
Verizon [17]

Answer:

4/10, 0.4, 40%

1/4, 0.25, 25%

Hope this helps also "Hi" again. :)

5 0
3 years ago
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