Answer:
the x² test statistic 13.71
Option a) 13.71 is the correct answer.
Step-by-step explanation:
Given the data in the question;
Feeder 1 2 3 4
Observed visits; 
60 90 92 58
data sample = 300
Expected 
= 300 / 4 = 75
the x² test statistic = ?
= ∑[ ( - )²/]
= [ (60 - 75)² / 75 ] + [ (90 - 75)² / 75 ] + [ (92 - 75)² / 75 ] + [ (58 - 75)² / 75 ]
= [ 3 ] + [ 3 ] + [ 3.8533 ] + [ 3.8533 ]
= 13.7066 ≈ 13.71
Therefore, the x² test statistic 13.71
Option a) 13.71 is the correct answer.
5-3(1/2x+2)=-7
-3(1/2x+2)=-7-5
(1/2x+2)=4
1/2x=2
x=4
just to give u an idea
Answer:
4x^2 -25
Step-by-step explanation:
The other factor of the difference of squares is the "conjugate" of the given one: (2x -5). Then their product is ...
(2x +5)(2x -5) = (2x)^2 -(5)^2 = 4x^2 -25
The answer is X= 5. Using the pythagorean theorem, and assuming that "b" is 3, half of 6 because the triangle is isosceles, you can solve the problem.
Since you are given that the student registered early, the total number you deal with is all students who registered early.
211 + 329 = 540
number of undergraduates who registered early = 211
Among students who registered early:
p(undergraduate) = 211/540
