For AD:
AD=root((c-0)^2 + (d-0)^2)=root((c)^2 + (d)^2)
For BC:
BC=root(((b+c) - b)^2+(d-0)^2)=root((c)^2+(d)^2)
For AB:
AB=root((b-0)^2 + (0-0)^2)=root((b)^2 + (0)^2)=root((b)^2)
For CD:
CD=root((c-(b+c))^2 + (d-d)^2)
CD=root((b)^2 + (0)^2)
CD=root((b)^2)
This is what I found, I hope it helps! Good luck with your test
Answer:
░░░░░▐▀█▀▌░░░░▀█▄░░░
░░░░░▐█▄█▌░░░░░░▀█▄░░
░░░░░░▀▄▀░░░▄▄▄▄▄▀▀░░
░░░░▄▄▄██▀▀▀▀░░░░░░░
░░░█▀▄▄▄█░▀▀░░
░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob
▄░▐░░░▄▄░█░▀▀ ░░
▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers
░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take
░░░░░░░▀███▀█░▄░░ Over brainly
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░░░░░░▐▀░░░░░░▐▌░░
░░░░░░█░░░░░░░░█░
do it or he will hunt you down and kill u (lets destroy the moderators!!!!!!!!)
we are slowing them down already! good work soilders!
JOIN THE BOB GANG!!!!!!!!!
Step-by-step explanation:
It’s 2.042
Have a great day! :D
Answer:
A. 
Step-by-step explanation:
We have the expression
![log_{3} (\sqrt[5]{x} *y)](https://tex.z-dn.net/?f=log_%7B3%7D%20%28%5Csqrt%5B5%5D%7Bx%7D%20%2Ay%29)
As these two values are being multiplied, we can separate the two and the sum of them will be equal to the multiplied version
![log_{3}\sqrt[5]{x} +log_{3}y](https://tex.z-dn.net/?f=log_%7B3%7D%5Csqrt%5B5%5D%7Bx%7D%20%2Blog_%7B3%7Dy)
The
can be rewritten as
. This allows us to use the exponent rule. This means that it can be written as
