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avanturin [10]
2 years ago
9

For which distributions is the median the best measure of center? Select each correct answer. Y 20 30 18 25 16 20 14 15+ 12 10+

10- 5+ 8 0 6 4 2 X 0 Y 24 20 22 18 20 = 16 18 14 16- 12 14 10 12 8 10 6 B 4 2 4 -X 2​

Mathematics
1 answer:
AURORKA [14]2 years ago
3 0

Answer:

The median is the best measure of center for distributions C and D.

Step-by-step explanation:

The <u>median</u> is the best measure of center for skewed distributions or distributions with outliers because it is a <u><em>robust</em></u> statistic, meaning that outliers and skewed data have <em>little effect </em>on the median.

Meanwhile, the <u>mean</u> is a good measure of center for symmetric distributions since it is <u><em>non-robust</em></u>.

Answer A has a roughly symmetric distribution, and answer B has a uniform distribution.

Answer C has a left-skewed distribution, and answer D seems to have a right-skewed distribution (since the right tail is longer than the left tail).

Therefore, the <u>median</u> would be the <u><em>best measure of center</em></u> for choices C and D.

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Consider the equation below.
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Answer:

Equation in square form:

y=3(x+5)^2-4

Extreme value:

(h,k)=(-5,-4)

Step-by-step explanation:

We are given

y=3x^2+30x+71

we can complete square

y=3(x^2+10x)+71

we can use formula

a^2+2ab+b^2=(a+b)^2

y=3(x^2+2\times x\times 5)+71

now, we can add and subtract 5^2

y=3(x^2+2\times x\times 5+5^2-5^2)+71

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Extreme values:

we know that this parabola

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so, we can compare it with

y=a(x-h)^2+k

where

vertex=(h,k)

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