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Alja [10]
3 years ago
11

Let U = {b1, b2, , bn} with n ≥ 3. Interpret the following algorithm in the context of urn problems. for i is in {1, 2, , n} do

for j is in {i + 1, i + 2, , n} do for k is in {j + 1, j + 2, ..., n} do print bi, bj, bk How many lines does it print? It prints all the possible ways to draw three balls in sequence, without replacement. It prints P(n, 3) lines. It prints all the possible ways to draw an unordered set of three balls, without replacement. It prints P(n, 3) lines. It prints all the possible ways to draw three balls in sequence, with replacement. It prints P(n, 3) lines. It prints all the possible ways to draw an unordered set of three balls, without replacement. It prints C(n, 3) lines. It prints all the possible ways to draw three balls in sequence, with replacement. It prints C(n, 3) lines.

Computers and Technology
1 answer:
viva [34]3 years ago
7 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image for the first step

Note that the -print" statement executes n(n — I)(n — 2) times and the index values for i, j, and k can never be the same.  

Therefore, the algorithm prints out all the possible ways to draw three balls in sequence, without replacement.

Now we need to determine the number of lines this the algorithm print. In this case, we are selecting three different balls randomly from a set of n balls. So, this involves permutation.  

Therefore, the algorithm prints the total  

P(n, 3)  

lines.  

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Answer:

def future_investment_value(investment, monthly_interest_rate, years):

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   print("- - - - - - - - - - -")

   for i in range(1, years+1):

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year = int(input("Enter the year: "))

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