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Alja [10]
3 years ago
11

Let U = {b1, b2, , bn} with n ≥ 3. Interpret the following algorithm in the context of urn problems. for i is in {1, 2, , n} do

for j is in {i + 1, i + 2, , n} do for k is in {j + 1, j + 2, ..., n} do print bi, bj, bk How many lines does it print? It prints all the possible ways to draw three balls in sequence, without replacement. It prints P(n, 3) lines. It prints all the possible ways to draw an unordered set of three balls, without replacement. It prints P(n, 3) lines. It prints all the possible ways to draw three balls in sequence, with replacement. It prints P(n, 3) lines. It prints all the possible ways to draw an unordered set of three balls, without replacement. It prints C(n, 3) lines. It prints all the possible ways to draw three balls in sequence, with replacement. It prints C(n, 3) lines.

Computers and Technology
1 answer:
viva [34]3 years ago
7 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image for the first step

Note that the -print" statement executes n(n — I)(n — 2) times and the index values for i, j, and k can never be the same.  

Therefore, the algorithm prints out all the possible ways to draw three balls in sequence, without replacement.

Now we need to determine the number of lines this the algorithm print. In this case, we are selecting three different balls randomly from a set of n balls. So, this involves permutation.  

Therefore, the algorithm prints the total  

P(n, 3)  

lines.  

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Write a piece of codes that asks the user to enter a month (an integer), a day (another integer), and a two-digit year. The prog
Sliva [168]

Answer:

Follows are the code to this question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

int day,month,year;//defining integer variable

cout<<"please enter last two digit of the year: "; //print message

cin>>year;//input year value

cout<<"enter day: "; //print message

cin>>day;//input day value

cout<<"enter month: ";//print message

cin>>month;//print month message

if(month*day==year)//check magic date condition  

{

cout<<"its magic programology year";//print message

}

else

{

cout<<"its not magic year";//print message

}

return 0;

}

Output:

please enter last two digit of the year: 98

enter day: 14

enter month: 7

its magic programology year

Explanation:

In the given code, three integer variable "day, month, and year" is declared, that uses the input method "cin" to input the value from the user-end.

In the next step, an if block statement is used that check month and day value multiple is equal to year value, if the condition is true it will print "magic programology year" otherwise it will print "not the magic year".

6 0
3 years ago
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Answer:

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E-business is also known as the online business where online transactions take place.

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Explanation:

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