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zhannawk [14.2K]
3 years ago
7

Choose the function that shows the correct transformation of the quadratic function shifter eight units to the left and one unit

down.
A. f(x)=(x-8)^2-1

B. f(x)=(x-8)^2+1

C. f(x)=(x+8)^2-1

D. f(x)=(x+8)^2+1
Mathematics
1 answer:
romanna [79]3 years ago
8 0

Answer:

<em>The function that shows the correct transformation of the quadratic function shifter eight units to the left and one unit down is: </em>

Option C. f(x)=(x+8)^2-1

Step-by-step explanation:

If we have a function f(x) then we can move its graph horizontally making the transformation y = f(x + c)

Then if c> 0 the graph will move c units to the left.

If c the graph will move c units to the right.

If we apply the transformation y = f(x) + h then the graph of f(x) will move vertically h units.

If h> 0 the displacement will be h units up

If h the displacement will be h units down.

In this problem we have the parent function y = x ^ 2 and we want to move 8 units to the left and 1 unit to the bottom.

Then we apply the transformations described above with c = 8.

y = f(x + 8) = (x + 8) ^ 2

Now we must move the function 1 unit down, with h = -1.

y = f(x + 8) -1 = (x + 8) ^ 2 -1

f(x)= (x + 8) ^ 2 -1

<u><em>The answer is option C</em></u>

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Given:

A figure of a circle. KJ=6,KL=x-2,ML=4.

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According to the tangent secant theorem:

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