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kondaur [170]
2 years ago
8

Mark bought a house in 1995 for $200,000. His house has appreciated 4 % every year since he bought it. How much is his house wor

th today?
Mathematics
2 answers:
Svetach [21]2 years ago
7 0

Answer:

the worth of the house today is $392,000

Step-by-step explanation:

in 1995 --------- $200,000

and its appreciates by 4% yearly

so by 2019 the house will be

firstly we subtract 2019 from 1995 to know how many years the house has appreciated for

2019 - 1995 = 24years

therefore to get the total % the house has appreciated for we multiply the year by 4%

24 * 4% = 96%

so to get the appreciated value we multiply 96% by the initial amount of the house

96% * $200,000 = $192,000

therefore the worth of the house at present will be the initial amount plus the appreciated value

$200,000 + $192,000 = $392,000

Hoochie [10]2 years ago
4 0

Answer:

$533,167

Step-by-step explanation:

From the question,Mark bought a house in 1995(25 years ago more or less) for $200,000.

His house has appreciated four percent every year since he bought it.

How much is his house worth today

Let P = price of the house in 1995 or initial amount paid for the house

r = percent it appreciates each year or the growth rate

and n = number of years of appreciation( in this case 25 years since we are in 2020)

= P*(1+r/100)^n

or for this particular example of exponential growth

200,000×[(1+4/100)^25]

= 200000×2.6658...6

= 533,167.3

= $533,167

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Find the area of the shaded region. round answers to the nearest tenth. assume all inscribed polygons are regular. 29.3 units2
FromTheMoon [43]
The picture in the attached figure

we know that
the area of the shaded region is equal to
(2/3)*[area of the circle - the area of the triangle]  

step 1
Find the area of a circle Ac
Ac = π r²
Ac = π (6)²
Ac = 113.10 units²

step 2
find the area of the triangle At
The triangle is an equilateral triangle with angles on each corner equal to 60 degrees. Meanwhile,
the 3 angles at the center is 120 degrees each since a circle is 360 degree.
 We know that the radius (line from centerpoint to corner) is equivalent to 6.
Using the cosine law,
we can calculate for the length of one side.
s² = 6^ + 6² – 2 (6) (6) cos 120
s² = 108
s = 10.4 units
Since this is an equilateral triangle, therefore, all sides are equal.
The area for this is:
At = (sqrt3 / 4) * s²
At = 46.77 units²

step 3
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