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Alex_Xolod [135]
4 years ago
13

Through:(4,4),parallel to y=-6x +5

Mathematics
1 answer:
ad-work [718]4 years ago
6 0

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

In this case we have the following equation of the line:

y = -6x + 5

Where:

m = -6

By definition, if two lines are parallel then their slopes are equal. Thus, a parallel line will have an equation of the form:

y = -6x + b

Substitute the given point(x, y) :( 4,4)to find "b":

4 = -6 (4) + b\\4 = -24 + b\\4 + 24 = b\\b = 28

Finally, the equation of the requested line is:

y = -6x + 28

Answer:

y = -6x + 28

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A puzzle book cost $4.25. A NOVELCOST $9.70 more than the puzzle book. Which is the most reasonable estimate for the total cost
NNADVOKAT [17]

Answer:

$18

Step-by-step explanation:

$4.25 + $9.70 + $4.25 = $18.20

3 0
3 years ago
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Hector is flying a kite. He has let out 86 feet
Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is 42.258333^{0} ≅ 42.26^{0}

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = \frac{opposite}{hypotenus}

Sin 42.26^{0} = \frac{x}{86}

⇒ x = 86 x Sin 42.26^{0}

      = 86 x 0.6725

     = 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

                                    = 57.84 + 4

                                   = 61.84 feet

7 0
3 years ago
Please Help!<br><br> if these two shapes are similar, what is the measure of missing length q?
Maslowich
60 / 96 = 25 / q
5 / 8 = 25 / q
5*q = 8 * 25
5q = 200
q = 40

Check:
60 / 96 = 25 / 40
5/8 = 5/8 :)
5 0
3 years ago
Read 2 more answers
17.
Marta_Voda [28]

Answer:

a) 50 meters

b) 2354 meters

c) 12 seconds

d) 24.13 seconds

Step-by-step explanation:

Hello!

<h3>a) How far is Lincoln above the ground when he shoots the gun?</h3>

We need to really understand what the variables represent in this question. Given that t is time, and h is height, the time at which he shoots the bullet will be 0, as the bullet hasn't started traveling yet. This means that we can solve for the original height of the bullet by plugging in 0 for time in the equation.

Equation: h = -16t^2 + 384t + 50

Plug in 0 for t:

  • h = -16t^2 + 384t + 50
  • h = -16(0)^2 + 384(0) + 50
  • h = 50

The height at which Lincoln shot the bullet is 50 meters.

We can also look at this graphically. The height of origin will simply be when the x-value (in this case t-value) is 0. That means it is the point at which the graph intersects the y-axis, known as the y-intercept.

Standard form of a Parabola: y = ax^2 + bx + c

The y-intercept is the "c" value.

Given our equation: h = -16t^2 + 384t + 50

The c-value is 50. This proves that the y-intercept is 50.

<h3 /><h3>b)How high does the bullet travel vertically relative to the ground?</h3>

We want to find the highest point of the graph. To do that, we can find the vertex.

We can utilize the Axis of Symmetry (AOS) to find the Vertex.

First, find the AOS using the formula: AOS = -\frac{b}{2a}

  • a = -16
  • b = 384

Plug it into the formula:

  • AOS = -\frac{b}{2a}
  • AOS = -\frac{384}{2(-16)}
  • AOS = \frac{384}{32}
  • AOS = 12

Plug in 12 for t in the equation:

  • h = -16t^2 + 384t + 50
  • h = -16(12)^2 + 384(12) + 50
  • h = -2304 + 4608 + 50
  • h = 2304+50
  • h = 2354

Therefore, the highest point of the bullet is 2354 meters.

<h3>c)How long does it take the bullet to reach its greatest height?</h3>

We answered this in the last question. The t-value when h is at its highest is 12.

<h3>d)After how many seconds (round to nearest 100th) does the bullet hit the ground?</h3>

We have to solve for the values of t when h is 0 (when it touches the ground).

Set the equation to 0, and solve using the quadratic formula.

Quadratic formula: x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}

  • x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}
  • x = \frac{-384\pm\sqrt{384^2 - 4(-16)(50)}}{2(-16)}
  • x = \frac{-384\pm\sqrt{147456 +3200}}{-32}
  • x = \frac{-384\pm\sqrt{150656}}{-32}
  • x = \frac{-384\pm388.14}{-32}
  • x = -\frac{4.14}{32}, x = \frac{772.14}{32}

We are only going to take the positive solution, as we can't have a negative time. The solution that doesn't work is called an extraneous solution.

  • x = \frac{772.14}{32}
  • x = 24.13

It takes approximately 24.13 seconds for the bullet to hit the ground.

6 0
2 years ago
How do i graph this
sergey [27]
Choose one of two ways to use the axis lines or choose your own numbers.
3 0
4 years ago
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