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Anon25 [30]
3 years ago
7

In a paint factory, an old conveyer line has filled 10 barrels of paint, and is filling more at a rate of 2 barrels per minute.

A worker just switched on a newer line that can fill 3 barrels per minute. In a little while, the two lines will have filled an equal number of barrels. How many barrels will each line have filled?
Simplify and put into Slope-Intercept form
Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

First line:

y = mx+b  where m is the slope and b is the y intercept

y = 2x + 10

Second line

y = mx+b

y = 3x+0  since there are no barrels filled on this line when they flip the switch

Setting the two equations equal

2x+10 = 3x

Subtract 2x from each side

2x+10-2x= 3x-2x

10 = x

Each line will have filled 10 barrels when they numbers are equal.

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Pen are shipped to the office supply store in boxes of 12 each. Write a function rule to calculate the total number of pens when
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p = 12x is the  function rule to calculate the total number of pens when you know the number of boxes

<em><u>Solution:</u></em>

Given that,

Pen are shipped to the office supply store in boxes of 12 each

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Let "p" be the total number of pens

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p = x \times 12\\\\p = 12x

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3 years ago
If -10 is subtracted from a number, the result is 6. what is the number?
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3 0
3 years ago
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9660 divided by 23 ( SHOW YOUR WORK PLEASE ) <br><br> It's for a grade to turn in Handwritten notes
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Answer:

420

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What is the equation of a parabola y(x) that has a vertex at point (− 1/3 , 0.3) and passes through point (− 2/15 , − 1/2 ).
Savatey [412]

bearing in mind that 0.3 = 3/10


\bf ~\hfill \textit{parabola vertex form}~\hfill \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{we'll use this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-\frac{1}{3}}{ h},\stackrel{\frac{3}{10}}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y=a\left[ x-\left( -\cfrac{1}{3} \right) \right]^2+\cfrac{3}{10}\implies y=a\left( x+\cfrac{1}{3} \right)^2+\cfrac{3}{10}


\bf \textit{we also know a point } \begin{cases} x=-\frac{2}{15}\\\\ y=-\frac{1}{2} \end{cases}\implies -\cfrac{1}{2}=a\left( -\cfrac{2}{15}+\cfrac{1}{3} \right)^2+\cfrac{3}{10} \\\\\\ -\cfrac{1}{2}-\cfrac{3}{10}=a\left( \cfrac{1}{5} \right)^2\implies -\cfrac{4}{5}=a\left(\cfrac{1}{25} \right)\implies -\cfrac{4}{5}=\cfrac{a}{25}\implies \cfrac{-4\cdot 25}{5}=a \\\\\\ -4\cdot 5=a\implies \boxed{-20=a} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-20\left( x+\cfrac{1}{3} \right)^2+\cfrac{3}{10}~\hfill

8 0
3 years ago
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