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irina1246 [14]
3 years ago
10

Grey, Inc., uses a predetermined rate to apply overhead. At the beginning of the year, Grey estimated its overhead costs at $220

,000, direct labor hours at 55,000, and machine hours at 20,000. Actual overhead costs incurred were $233,250, actual direct labor hours were 62,000, and actual machine hours were 15,000.
If the predetermined overhead rate is based on machine hours, what is the total amount credited to the factory overhead account for the year for Grey?

a. $215,000
b. $165,000
c. $240,000
d. $135,000
Business
1 answer:
NARA [144]3 years ago
7 0

Answer:

The answer is b.$165,000

Explanation:

Please find the below for detail explanations and calculations:

As Grey's predetermined overhead rate is based on machine hours, it is calculated as:

Predetermined overhead rate = Estimated overhead costs / Estimated machine hours = 220,000 / 20,000 = $11 per a machine hour.

The amount credited to the factory overhead account for the year for Grey is calculated as:

Overhead cost = Predetermined overhead rate x Actual machine hour = 11 x 15,000 = $165,000.

Thus, the answer is b.$165,000

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mafiozo [28]

Answer:

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Explanation:

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The $25 per hour forgone by working on the farm land is implicit cost.

                       

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<h3>Answer:</h3>

<h3>Explanation:</h3>

The formula for calculating the Monthly payments P for the sinking fund is as follows:

P\;=\;\frac{A*i}{(1+i)^n-1}

where,

P = Monthly payments to be made

A = Total amount to be accumulated

i = Interest rate for given time period

n = Number of time period

Assuming interest is applied at the beginning of each period.

We are given two scenarios.

<h3><u>Scenario (i) - Deposit is made during the year:</u></h3>

In this scenario, as some of the year is already passed (assume 6 months), to complete the time period of 3.5 years the interest will compound 3 times (as the 0.5 year payments can be adjusted in the remaining part of the first year and no interest is applied on it). Hence, the interest will be applied 3 times.

\therefore P_{(i)}\;=\;\frac{5000*0.08}{(1+0.08)^3-1}\\\\P_{(i)}\;=\;\frac{400}{0.2597}\\\\P_{(i)}\;=\;1540.1676

<h3><u>Scenario (ii) - Deposit is made at the beginning of the year:</u></h3>

For this case, the interest will be applied 4 times to complete the time period of 3.5 years for payment.

\therefore P_{(ii)}\;=\;\frac{5000*0.08}{(1+0.08)^4-1}\\\\P_{(ii)}\;=\;\frac{400}{0.3605}\\\\P_{(ii)}\;=\;1109.6040

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<span>
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