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vladimir1956 [14]
4 years ago
5

A simple random sample of size n is drawn from a normally distributed population, and the mean of the sample is (x with a line o

ver it), while the standard deviation is s. What is the 99% confidence interval for the population mean? Use the table below to help you answer the question.
Confidence Level. 90%. 95%. 99%
z*-score. 1.645. 1.96. 2.58

Mathematics
2 answers:
lutik1710 [3]4 years ago
6 0

Answer:

the answer is the (1.645 over root of n) on e 2020

Step-by-step explanation:

prohojiy [21]4 years ago
3 0

Answer:

Last option

{\displaystyle {\overline {x}}} \± \frac{2.58*s}{\sqrt{n}}

Step-by-step explanation:

{\displaystyle {\overline {x}}}

If we extract a sample of size n from a normal population and we want to estimate the population mean then the confidence interval for the mean will be:

{\displaystyle {\overline {x}}} \± Z_{\alpha/ 2}*\frac{s}{\sqrt{n}}

Where

Where {\displaystyle {\overline {x}}}  is an estimator for the mean μ.

n is the sample size and s is its standard deviation.

\alpha is the level of significance

\alpha= 1-Confidence Level

\alpha= 1-0.99

\alpha = 0.01

Then Z_{\frac{\alpha}{2}} = Z_{\frac{0.01}{2}} = Z_{0.005}=2.58

Then the 99% confidence interval for the population mean is

{\displaystyle {\overline {x}}} \± \frac{2.58*s}{\sqrt{n}}

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