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Alexandra [31]
3 years ago
12

Simplify: –3y 2x – 10y – 5x 2y a. –11y – 3x b. –15y 3x c. –15y – 3x d. –11y 7x

Mathematics
1 answer:
hoa [83]3 years ago
5 0
The answer is A.<span>–11y – 3x</span>
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A section of a boardwalk is made using 15boards. Each board is 9/1/4 inches wide. The total width of the section is 144 inches.
sleet_krkn [62]
If there are 15 boards there are 14 gaps in-between. 
But first, 15 boards each 9 and 1/4th inches so you get  a total of 138 inches and 3/4th
If you subtract that from 144 you get 5 inches and 1/4th. The remaining amount is the total of all of the distance from the spacing.
Then you divide that by 14 (number of gaps/spacing in-between.)
So you get .375 inches. (3/8)
So width of the spacing between each board is 3/8ths of a inch
4 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
tatiyna

Answer:

The product of 3a^2.2a^3\\ is 6a^6

Step-by-step explanation:

We need to find the product of 3a^2.2a^3\\

Using the exponent rule: a^m. a^n = a^{m*n}

So,

3a^2.2a^3\\

Applying above rule:

3.2 (a^{2*3})\\

6a^6

So, the product of 3a^2.2a^3\\ is 6a^6

8 0
3 years ago
Three-quarters of a number is 15.<br> Work out four-fifths of the number.
azamat

Answer:

16

Step-by-step explanation:

let the number be x , then

\frac{3}{4} x = 15 ( multiply both sides by 4 to clear the fraction )

3x = 60 ( divide both sides by 3 )

x = 20 , then

\frac{4}{5} × 20 = 4 × 4 = 16

3 0
2 years ago
Read 2 more answers
Does anyone know what math topic this is?
katen-ka-za [31]

Answer:

If you're talking about things like Algebra and Geometry, its Geometry

If you're not, can you be more specific ? :D

3 0
3 years ago
Read 2 more answers
If 2tanA=3tanB,then prove that tan(A-B)=sin2B/(5-cos2B) ...?
andreev551 [17]
Tan ( A - B ) = ( tan A - tan B ) / ( 1 + tan A tan B )
tan A = 3 tan B/2
tan ( A - B ) = ((3 tan B/ 2)-tan B) / ( 1 + 3 tan² B/2)=
= (tan B/2)  / ( 2 + 3 sin²B/cos²B )=
= (sin B / cos B) / (( 2cos² B+3sin²B)/cos²B)=
=( sin B cos B ) / ( 2 cos²B + 3 ( 1 - cos² B ) ) =
= (sin B cos B ) / ( 2 cos² B + 3 - 3 cos² B ) =
= ( sin 2 B ) / 2 ( 3 - cos² B ) =
= ( sin 2 B ) / ( 6 - cos² B )=
= ( sin 2 B ) / ( 5 + 1 - 2 cos² B )=
= ( sin 2 B ) / ( 5 + sin² B + cos ² B - 2 cos² B ) =
= ( sin 2 B ) / ( 5 - ( cos² B - sin² B ) ) =
= ( sin 2 B ) / ( 5 - cos 2 B )  - correct 
8 0
2 years ago
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