Plug in 10/3
9(10/3)-19= 3(10/3)+1
30-19= 10+1
11=11
That is the solution.
I hope this helps!
~kaikers
Answer:
Example: the median is not affected by very large or very small values (outliers).
Step-by-step explanation:
Suppose my income for 5 months is $1000, $1500, $1550, $2000, $90,000. (I hit the lottery in the last month!).
The median is the number in the middle: $1550. That $90,000 would increase the <u>mean</u> ("average") by a lot, but the median is unchanged.
If a newspaper story reports the median house price in a neighborhood is $93,000, that million dollar mansion on the corner won't change the median. Half the prices are less than $93,000 and half are greater.
Answer:
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Complemento porque Es menos de 90 graus
Answer:
q = 5000/x + 6
Step-by-step explanation:
D´= dq/dx = - 5000/x²
dq = -( 5000/x²)*dx
Integrating on both sides of the equation we get:
q = -5000*∫ 1/x²) *dx
q = 5000/x + K in this equation x is the price per unit and q demanded quantity and K integration constant
If when 1006 units are demanded when the rice is 5 then
x = 5 and q = 1006
1006 = 5000/5 +K
1006 - 1000 = K
K = 6
Then the demand function is:
q = 5000/x + 6
