Answer:
Step-by-step explanation:
√108 ÷ √125 + √75
= 6√3 ÷ 5√5 + 5√3
= 11√3 / 5√5
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Y=Acos(p)+m, A=amplitude, p=period, m=midline, in this case:
A=1/2, p=360(t/12)=30t, m=(10-9)/2+9=9.5 so
h(t)=(1/2)cos(30t)+9.5
The point (-1,2) is in quadrant 2
