All categories

3 years ago

Summarize the order of operations for evaluating expressions. Use complete sentences.

1 answer:

6 0

<span>PEMDAS
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

First, take into account if there are any brackets (parentheses) in the equation. Any equation within a bracket </span><span>(parentheses) must be performed first.

The next step is to solve any of the powers.

Thirdly, solve any of the multiplication and division. If there is both multiplication and division, work from left to right.

Finally, solve adding and subtraction. Again, if there is both, work from left to right.</span>

Hoped I helped!

You might be interested in

PLEASE HURRY ASAP I NEED IT ASAPP PLEASE SHOW YOUR WORKKK I WILL MAKE YOU BRAINLIEST

Arturiano [62]

Answer:

BD = √97 cm ≈ 9.849 cm

Step-by-step explanation:

Diagonal BD of rectangle ABCD is the hypotenuse of right triangle ABD. Opposite sides of the rectangle are the same length, so we have ...

AB = 4 cm

AD = 9 cm

The sides are related to the diagonals by the Pythagorean theorem.

<h3>Pythagorean theorem</h3>

The Pythagorean theorem tells you the relation between sides and hypotenuse of a right triangle:

AB² +AD² = BD²

4² +9² = BD² = 16 +81 . . . . . evaluating the squares

BD = √97 . . . . . take the square root

The length of BD is √97 cm, about 9.849 cm.

6 0

2 years ago

Mattie uses the discriminant to determine the number of zeros the q

enot [183]

Answer:for ax^2+bx+c=0 the discriminant is b^2-4ac

there are 3 basic cases of what happens for different discriminants

1. if the discriminant is less than 0, then there are no real zeroes

2. if the discriminant is 0, then it has 1 zero

3. if the discriminant is greater than 0, it has 2 zeroes

so given

0=3x^2-7x+4

a=3,b=-7,c=4

thus the discriminant is (-7)^2-4(3)(4)=49-48=1

the discriminant is 1. 1 is positive, thus the equation has 2 zeroes because the discriminant is greater than 0

the answer is the equation has two zeroes because the discriminant is greater than 0

Step-by-step explanation:

3 0

3 years ago

What are two square roots of 196

Alecsey [184]

The answer is 14 because 14×14=196

4 0

3 years ago

Add.<br> (-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)<br> express the answer in standard form.

Alex777 [14]

$(-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)\\\\=-x^3+26x^2-7-13+6x^4-x^3+8x+27\\\\=6x^4+(-x^3-x^3)+26x^2+8x+(27-7-13)\\\\=\boxed{6x^4-2x^3+26x^2+8x+7}$

4 0

3 years ago

Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a

Bond [772]

$f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x$

$f$ has critical points where $f'=0$ :

$3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi$

where $n$ is any integer. We get solutions in the interval $\left[0,\frac\pi3\right]$ for $n=0$ , for which $x=\frac\pi4$ .

At this critical point, we have $f\left(\frac\pi4\right)=3\sqrt2\approx4.243$ .

At the endpoints of the given interval, we have $f(0)=3$ and $f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098$ .

So we have the extreme values

$\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2$

$\min\limits_{x\in\left[0,\frac\pi3\right]}f=3$

8 0

3 years ago