
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer:
Step-by-step explanation:

If x = 0:
y > 2 × 0 - 5
y > - 5
If x = 3:
y > 2 × 1 - 5
y > 1
The coordenates (3, 1) and (0, -5) are not included.
Alternative A
I hope I helped you.
Answer:
x = -3
Step-by-step explanation:
Answer:
x = 22.5°
Step-by-step explanation:
m∠DEA = 2x
DE || AB
m∠EAB = 2x - by Alternate Interior Angles
Exterior angle = 6x, which equals 2x + 4x
m∠BEA = 4x
Exterior Angle 4x = 2x + 2x
m∠B = 2x
2x + 4x + 2x = 180°
8x = 180°
x = 22.5°
<h2>Exterior Angles of a Triangle:</h2>
An exterior angle of a triangle is equal to the two REMOTE angles inside the triangle.
In this example, we know that 6x has remote angles of ∠EAB and ∠BEA
We found out that m∠EAB = 2x, so m∠BEA must equal 6x - 2x or 4x
<h2>Sum of angles in a Triangle:</h2>
The sum of all angles in a triangle is equal to 180°.
In this example, we found all the angles, 2x, 4x, 2x. We added all of those values to equal 8x
Since the sum of all angles = 180°:
8x = 180°
x = 180°/8
x = 22.5°
-Chetan K