Factor the polynomial below. 6x3y3z 12x2y2z3

Mathematics

2 answers:

laiz [17]3 years ago

8 0

<span>The answer is 6x^2y^2z(xy+2z^2).</span>

natka813 [3]3 years ago

8 0

Answer:

$6x^2y^2z(xy+2z^2)$

Step-by-step explanation:

We are asked to factor our given polynomial.

$6x^3y^3z+12x^2y^2z^3$

We can see that the GCF of our given polynomial is $6x^2y^2z$ .

Upon factoring out $6x^2y^2z$ from our given polynomial we will get,

$6x^2y^2z(xy+2z^2)$

Therefore, the factored form of our given polynomial would be $6x^2y^2z(xy+2z^2)$ .

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How many milliequivalents of sodium chloride are contained with 3 L of normal saline?

AVprozaik [17]

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

$3000ml*\frac{0.9g}{100ml}=27g=27000mg$

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation ( $mEq=\frac{mg}{pE}$ ) where pE is de molecular mass of NaCl divided by their charges, in this case 1: