9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
4g and 6b and that's a total of 10 in all so you know it will be 1/2 if its going to be two out of two
List the coordinates,
Coordinates are shown as (x,y)
If 2+2+7+7 is 16
You make those your side lengths
Coordinates are (9,7) (2,7) (2,5) (9,5)
they maybe slightly off because of the broken peice of paper
They can not, there are only 2 sides and they probably flipped it different ways. They got 'lucky'.
Answer:
f=14 or f=34
Step-by-step explanation:
(x+d)(x+e) =x^2 +fx+33, d, e, f>0
x^2 +xe+dx+de=x^2+fx+33
x^2+(e+d)x+de=x^2 +fx+33 that
e+d=f and d*e=33, d=33/e
e+33/e=f
33=1*33 or 33=3*11
If e=1,d=33 then f=34
If e=3*,d=11, then f=14
