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Alekssandra [29.7K]
3 years ago
8

Twice the sum of six "x" and seventy eight.

Mathematics
1 answer:
kogti [31]3 years ago
6 0

Answer:

2(6x+78)

Unless it's the exact number. You hadn't specified what x is.

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Evaluate the expression 5(8y+3r-5z) if r=3,y=5/8,and z=2
snow_lady [41]
First you plug in the missing values
5(8×5/8+3×3-5×2) = 20
3 0
3 years ago
What is the reciprocal of –5?
Anon25 [30]
-5 is the same as -5/1

Flip the fraction:

-1/5

2/9 / 1/4

Flip the 2nd fraction and multiply:

2/9 * 4/1

Multiply the numerators and denominators:

8/9
4 0
3 years ago
Read 2 more answers
Frank has devised a formula for his catering business that calculates the number of meat balls he needs to prepare the formula i
ira [324]

Answer:

96 meatballs are required

Step-by-step explanation:

We know that the formula for he catering business is

m=4a+2c

Where

c= the number of children, m=the number of meat balls, a= the number of adults

So if c = 8  and a = 20 then

m = 4(20) + 2(8)

m = 80 + 16

m = 96

Finally  96 meatballs are required for the party

4 0
3 years ago
ASAP in 4 math question!
Zepler [3.9K]

1. - 4 = \frac{x}{9}

=> x = - 36

___________

2. -18 = 6t

=> t = \frac{-18}{6}

=> t = -3

___________

3. x - 18 = -72

=> x = - 72 + 18

=> x = - 54

___________

4. -18 = x - 15

=> x = -18 + 15

=> x - 3

7 0
2 years ago
Use the discriminant to determine the number of solutions and types of solutions for the quadratic equation, below. Then answer
Setler79 [48]

Answer:

A. Discriminant = 116

B. Number of solutions for the quadratic equation = 2

C. Type of solutions (circle one):Imaginary

D. Type of solutions (circle one):irrational

Step-by-step explanation:

The given quadratic equation is

{x}^{2}  + 8x = 13

We rewrite in standard form to get;

{x}^{2}  + 8x   - 13 = 0

The discriminant is

D =  {b}^{2}  - 4ac

where a=1, b=8, c=-13

We substitute to get:

D =  {8}^{2}  - 4 \times 1 \times  - 13

D = 64  + 52

D = 116

Since the discriminant is great than zero, we have two distinct real roots

6 0
3 years ago
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