H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer:
t=11,11 days
Step-by-step explanation:
F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating
⇒ LnF=Kt+c,
; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)),
⇒
, so
, now if F=130, t=? we have:

The expression that models the length of the second leg of the triangle is <u>2x - 3.</u>
<u><em>Recall</em></u>:
The area of a triangle = 
<em><u>Given</u></em>:
Area of triangle = 
Length of one of the legs = 3x + 1
Therefore, it means that multiplying both legs should give us:

To find the expression that models the other leg, divide
by 3x + 1:



Therefore, the expression that models the length of the second leg of the triangle is <u>2x - 3.</u>
<u></u>
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brainly.com/question/20712284