Answer:
9 and 11
Step-by-step explanation:
First number = x -2
Second number = x
and 2x = 3(x-2) - 5
2x = 3x - 6 - 5
x = 11
first number = 11-2 = 9
• Expand (2a + b)²:
(2a + b)²
= (2a + b) · (2a + b)
Multiply out the brackets by applying the distributive property of multiplication:
= (2a + b) · 2a + (2a + b) · b
= 2a · 2a + b · 2a + 2a · b + b · b
= 2²a² + 2ab + 2ab + b²
Now, group like terms together, and you get
= 2²a² + 4ab + b²
= 4a² + 4ab + b² <——— expanded form (this is the answer).
I hope this helps. =)
Tags: <em>special product square of a sum algebra</em>
The question is written unclear.
my guess would be 24:7 (24/7)
Marked(10)/total = 3/20 (from sample)
total/10 = 20/3 (inverting the above proportion)
total = 10•20/3 = 200/3 ≈ 67
