By the segment addition postulate,
AC + CE = AE so AC = AE - CE
AC = (x+50) - (x+32)
AC = x+50-x-32
AC = 18
<u>Let's consider the facts at hand</u>:
- By Vertical Angle Theorem ⇒ ∠BCE = ∠DCF
- ∠BEC = ∠DFC
- Sides BE = DF
<u>Based on the diagram, triangles BCE and triangles DCF are similar</u>
⇒ based on the Angle-Angle theorem
⇒ since ∠BCE = ∠DCF and ∠BEC = ∠DFC
⇒ the two triangles are similar
Hope that helps!
<em>Definitions of Theorem I used:</em>
- <u><em>Vertical Angle Theorem: </em></u><em>opposite angles of two intersecting lines must be equal</em>
- <u><em>Angle-Angle Theorem:</em></u><em> if two angles of both triangles are equal, then the given triangles must be similar</em>
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Answer:
b
Step-by-step explanation:
Answer:
x=1 and y=−1
Step-by-step explanation:
Use substitution in order to solve this.
Answer:
2 is ur answer
Step-by-step explanation:
