Answer:
A. 
B. 
Step-by-step explanation:
Consider the equation

A. This equation has no solutions when the coefficients at x are the same and the free coefficients are not the same.
First, use distributive property:

So, the equation is

This equation has no solutions when

B. The equation has infinitely many solutions when the coefficients at x are the same and the free coefficients are the same too.
So, the equation

has infinitely many solutions when

In other cases, the equation has a unique solution
Answer:
4a(5a + 1)
Step-by-step explanation:
Given
20a² + 4a ← factor out 4a from each term
= 4a(5a + 1)
Answer:
2p + q = 1
9p + 3q + 3 = 0
q = 1 - 2p
replace q = 1 - 2p into 9p + 3q + 3 = 0
9p + 3(1 - 2p) + 3 = 0
9p + 3 - 6p + 3 = 0
3p + 6 =0
3p = -6
p = -2
q = 1 - 2p
q = 1 -2(-2)
q = 1 + 4
q = 5
(-2 , 5)
there for the answer would be
{(-2, 5)}
Hopefully this was helpful <3 :3
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