3 years ago

G(x)=4x^2 what would be the table to graph?

Mathematics

1 answer:

Jlenok [28]3 years ago

5 0

Answer:

no you will not use a table

The answer is

g(x) = 4x

$g{x} = 4x { \: }^{2} = 8x$

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So, this integral is divergent.

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$