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3 years ago

Figure ABCD ≅ Figure MNOP.

Mathematics

1 answer:

slamgirl [31]3 years ago

5 0

I got 1/2. But for the abbreviation if they ask for it would be 1/2NO

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PLS ANSWER NOW WILL EARN BRAINLIEST IF RIGHT

kolbaska11 [484]

Answer:

I Know the answer because I am in k12 too.

The answer is 37.5%

Step-by-step explanation:

$80 - $50 = $30

$30 * 100 / $ 80 = 37.5%

answer: 37.5% of decrease.

5 0

3 years ago

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Each year Taylor donates 1/10 of her annual income to local charities. One-fifth of that amount goes to a charity that supports

Soloha48 [4]

Answer:

ITS CORRECT

Step-by-step explanation:

THE ANSWER IS 0.02 OR 1/50

4 0

3 years ago

What is the percent correct for a quiz score of 14 points out of 20.A.43%B. 53%C.70%D.75%

matrenka [14]

14 divided by 20 is 0.7
Multiply that by 100
The answer is 70%

6 0

3 years ago

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If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

4 years ago

The number of apples required to bake a pie varies directly with the square of the diameter of the pie tin. If 4 apples are requ

Lesechka [4]

Answer:

5 apples

Step-by-step explanation:

Solution,

4 apples are required for a pie tin with a diameter of 8 inches

For 1 inch of the pie tin 8/4=2 apples are required.

For 10 inches 10/2=5 apples are required.

5 0

3 years ago

Read 2 more answers