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andreev551 [17]
3 years ago
8

What is the area, in square inches, of the isosceles trapezoid below?

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Area of a trapezoid: (top + bottom)/2 x height

Area = (6.5 + 15.1)/2 x 5

Area = 21.6/2 x 5

Area = 10.8 x 5

Area = 54 square inches.

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Step-by-step explanation:

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Slav-nsk [51]
Since the figures are similar, we can establish a rule of three as follows.
We know that the area of the smaller figure is 25in^{2}, and its volume is 250in^{3}. We also know that the area of the larger figure is 36in^{2}; since we don't now its volume, lets represent it with X:
\frac{25in^{2}----\ \textgreater \ 250in^{3}}{36in^{2}----\ \textgreater \ Xin^{3}} 
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We can conclude that the volume of the larger figure is 360in^{3}; therefore, the correct answer is a.
6 0
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