3 years ago

What is the area, in square inches, of the isosceles trapezoid below?

Mathematics

1 answer:

Nostrana [21]3 years ago

3 0

Area of a trapezoid: (top + bottom)/2 x height

Area = (6.5 + 15.1)/2 x 5

Area = 21.6/2 x 5

Area = 10.8 x 5

Area = 54 square inches.

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ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x

fomenos

Answer:

A) x = 20

Step-by-step explanation:

ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.

Since, diagonals of a rhombus are perpendicular bisector.

$\therefore \: m \angle AED = 90 \degree \\ \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90 \\ \therefore \: 5x = 90 + 10 \\ \therefore \: 5x = 100 \\ \\ \therefore \: x = \frac{100}{5} \\ \\ \huge \red{ \boxed{ \therefore \: x =20}}$