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mr_godi [17]
3 years ago
13

Is the relation a function?

Mathematics
1 answer:
mario62 [17]3 years ago
6 0

Yes it is because none of the x are the same number making it a function.

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|<br> Find the amplitude and period of f(t)= 1/2sin3t
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Answer:

Step-by-step explanation:

hello :

note : y = A sin(Bt + C) + D

• amplitude is A

• period is 2π/B

in this exercice : f(t)= 1/2sin3t

amplitude is A =1/2

period is 2π/3

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3 years ago
tickets to a play cost $11 each. There is also a service charge of $4 per order. Write ab equation for the relationship that giv
abruzzese [7]
Y=11x+4. formula: y=mx+b. insert the number of tickets where x is times 11 then add 4 to your total
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A bag contains 5 red marbles , 2 blue marbles, 4 white marbles, and 1 yellow marble. if 2 marbles are chosen in a row , without
slega [8]
P of 1st white marble = 4/ 12

and P of 2nd white in a row = 3 /11

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3 years ago
Below is a table for f(x) = 3x + 1. Using the table, determine the value of x when f(x) = 13​
Elena L [17]
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7 0
2 years ago
Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of
ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that A(24) = (1-0.26)A(0) = 0.74A(0); We use this to find r.

A(t) = A(0)(1-r)^t

0.74A(0) = A(0)(1-r)^{24}

(1-r)^{24} = 0.74

\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}

1 - r = (0.74)^{\frac{1}{24}}

1 - r = 0.9875

r = 1 - 0.9875 = 0.0125

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that A(0) = 810

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 810(1 - 0.26)^t

A(t) = 810(0.74)^t

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

5 0
3 years ago
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